Lecture Notes in Functional Analysis

by William L. Paschke

edition 0.9

image/svg+xml

Contents

Frontmatter

I. Hilbert Space

II. Bounded Operators

III. Compact Operators

IV. The Spectral Theorem

Index and References

H. Operators on Tensor Products

Proposition II.69

Let Vvector space\( V \) and Wvector space\( W \) be vector spaces and φfunction1one∈element ofVvector space* \( {φ}_{1}\in V^{*} \) and φfunction2two∈element ofWvector space* \( {φ}_{2}\in W^{*} \) linear functionals. Then there is a unique linear functional φfunction1one⊗φfunction2two \( {φ}_{1}\otimes {φ}_{2} \) on Vvector space⊗Wvector space \( V\otimes W \) such that (φfunction1one⊗φfunction2two)⁡(xvector⊗yvector)=equalsφfunction1one⁡(xvector)⁢timesφfunction2two⁡(yvector) . \[ \mathopen{}\left({φ}_{1}\otimes {φ}_{2}\right)\mathclose{}\mathopen{}\left( x\otimes y\right)\mathclose{}= {φ}_{1}\mathopen{}\left( x\right)\mathclose{}{φ}_{2}\mathopen{}\left( y\right)\mathclose{} \text{.} \] for all xvector∈element ofVvector space\( x\in V \) and yvector∈element ofWvector space\( y\in W \).

Proof. The function defined by (xvector, yvector)↦is mapped toφfunction1one⁡(xvector)⁢timesφfunction2two⁡(yvector) \( \mathopen{}\left(x, y\right)\mathclose{}\mapsto {φ}_{1}\mathopen{}\left( x\right)\mathclose{}{φ}_{2}\mathopen{}\left( y\right)\mathclose{} \) is bilinear.

Proposition II.70

If ∑summationjinteger=1oneninteger xvectorjinteger⊗yvectorjinteger =equals0zero \( \sum_{j=1}^{n}{} {x}_{j}\otimes {y}_{j} = 0 \) where xvectorjinteger∈element ofVvector space \( {x}_{j}\in V \) and the yvectorjinteger∈element ofWvector space \( {y}_{j}\in W \) are linearly independent, then xvector1one=equals⋯=equalsxvectorninteger=equals0zero \( {x}_{1}= \dotsb= {x}_{n}= 0 \).

Proof. Since the yvectorjinteger\( {y}_{j} \) are linearly independent, there exist functionals φlinear functionaliinteger∈element ofWvector space* \( {φ}_{i}\in W^{*} \) such that φlinear functionaliinteger⁡(yvectorjinteger)=equalsδiintegerjintegerKronecker delta function \( {φ}_{i}\mathopen{}\left( {y}_{j}\right)\mathclose{}= \delta_{ij} \) where δiintegerjintegerKronecker delta function \( \delta_{ij} \) is the Kronecker δpositive real number\( δ \). Let τlinear functional∈element ofVvector space* \( τ\in V^{*} \). Then by Proposition II.69 we have 0zero=equals(τlinear functional⊗φlinear functionaljinteger)⁡(∑summationiinteger=1onenintegerxvectoriinteger⊗yvectoriinteger)=equals∑summationiinteger=1onenintegerτlinear functional⁡(xvectoriinteger)⁢timesφlinear functionaljinteger⁡(yvectoriinteger)=equals∑summationiinteger=1onenintegerτlinear functional⁡(xvectoriinteger)⁢timesδiintegerjintegerKronecker delta function=equalsτlinear functional⁡(xvectorjinteger) . \[ 0= \mathopen{}\left(τ\otimes {φ}_{j}\right)\mathclose{}\mathopen{}\left( \sum_{i=1}^{n}{}{x}_{i}\otimes {y}_{i}\right)\mathclose{}= \sum_{i=1}^{n}{}τ\mathopen{}\left( {x}_{i}\right)\mathclose{}{φ}_{j}\mathopen{}\left( {y}_{i}\right)\mathclose{}= \sum_{i=1}^{n}{}τ\mathopen{}\left( {x}_{i}\right)\mathclose{}\delta_{ij}= τ\mathopen{}\left( {x}_{j}\right)\mathclose{} \text{.} \] Thus τlinear functional⁡(xvectorjinteger)=equals0zero \( τ\mathopen{}\left( {x}_{j}\right)\mathclose{}= 0 \) for arbitrary τlinear functional\( τ \), and xvectorjinteger=equals0zero \( {x}_{j}= 0 \).

If HHilbert space1one\( {H}_{1} \) and HHilbert space2two\( {H}_{2} \) are Hilbert spaces and γmapping\( γ \) is a bounded bilinear map from HHilbert space1one×Cartesian productHHilbert space2two \( {H}_{1}\times {H}_{2} \) to a Hilbert space KHilbert Space\( K \), then the norm ‖γmapping⁡((tuplexvector, yvector)tuple)‖≤less than or equal tocreal number⁢times‖xvector‖⁢times‖yvector‖ \( \mathopen{}\left\lVert{}γ\mathopen{}\left( \mathopen{}\left(x, y\right)\mathclose{}\right)\mathclose{}\right\rVert\mathclose{}\leq c\mathopen{}\left\lVert{}x\right\rVert\mathclose{}\mathopen{}\left\lVert{}y\right\rVert\mathclose{} \) where creal number\( c \) is a constant. We know from our definition of the tensor product that γmapping\( γ \) may be associated with a bounded linear operator Tlinear map:mapsHHilbert space1one⊗HHilbert space2two→toKHilbert Space \( T : {H}_{1}\otimes {H}_{2} \to K \). It so happens that ‖Tlinear map‖=equals‖γmapping‖2two \( \mathopen{}\left\lVert{}T\right\rVert\mathclose{}= \mathopen{}\left\lVert{}γ\right\rVert\mathclose{}_{2} \).

Indeed, now that we have a norm structure, we might rephrase the original definition in terms of bounded linear mappings (see Kadison [6]). Here, we continue on to investigate bounded operators on HHilbert space⊗KHilbert Space \( H\otimes K \).

Theorem II.71

If Tbounded linear operator∈element ofℒbounded linear operators⁡(HHilbert space) \( T\in \mathcal{L}\mathopen{}\left( H\right)\mathclose{} \) and Sbounded linear operator∈element ofℒbounded linear operators⁡(KHilbert Space) \( S\in \mathcal{L}\mathopen{}\left( K\right)\mathclose{} \) are bounded, then the operator (Tbounded linear operator⊗Sbounded linear operator)⁡((xvector⊗yvector))=equalsTbounded linear operator⁡(xvector)⊗Sbounded linear operator⁡(yvector) \[ \mathopen{}\left(T\otimes S\right)\mathclose{}\mathopen{}\left( \mathopen{}\left(x\otimes y\right)\mathclose{}\right)\mathclose{}= T\mathopen{}\left( x\right)\mathclose{}\otimes S\mathopen{}\left( y\right)\mathclose{} \] is in ℒbounded linear operators⁡(HHilbert space⊗KHilbert Space) \( \mathcal{L}\mathopen{}\left( H\otimes K\right)\mathclose{} \) and is bounded.

Proof. If Iidentity operator\( \mathrm{I} \) is the identity operator, then it is easy to show Tbounded linear operator⊗Iidentity operator \( T\otimes \mathrm{I} \) and Iidentity operator⊗Sbounded linear operator \( \mathrm{I}\otimes S \) are bounded. Then Tbounded linear operator⊗Sbounded linear operator=equals(Tbounded linear operator⊗Iidentity operator)⁢times(Iidentity operator⊗Sbounded linear operator) \( T\otimes S= \mathopen{}\left(T\otimes \mathrm{I}\right)\mathclose{}\mathopen{}\left(\mathrm{I}\otimes S\right)\mathclose{} \) is bounded. The characterization of the tensor product shows Tbounded linear operator⊗Sbounded linear operator∈element ofℒbounded linear operators⁡(HHilbert space⊗KHilbert Space) \( T\otimes S\in \mathcal{L}\mathopen{}\left( H\otimes K\right)\mathclose{} \).

Exercise II.72

For Tbounded linear operator1one \( {T}_{1} \) and Tbounded linear operator2two \( {T}_{2} \) in ℒbounded linear operators⁡(HHilbert space) \( \mathcal{L}\mathopen{}\left( H\right)\mathclose{} \) and Sbounded linear operator1one \( {S}_{1} \) and Sbounded linear operator2two \( {S}_{2} \) in ℒbounded linear operators⁡(KHilbert Space) \( \mathcal{L}\mathopen{}\left( K\right)\mathclose{} \), bounded, and λcomplex number∈element ofCcomplex numbers \( λ\in \mathbb{C} \), the following hold:

  1. (λcomplex number⁢timesTbounded linear operator1one+plusTbounded linear operator2two)⊗Sbounded linear operator1one=equalsλcomplex number⁢times(Tbounded linear operator1one⊗Sbounded linear operator1one)+plusTbounded linear operator2two⊗Sbounded linear operator1one \( \mathopen{}\left(λ{T}_{1}+{T}_{2}\right)\mathclose{}\otimes {S}_{1}= λ\mathopen{}\left({T}_{1}\otimes {S}_{1}\right)\mathclose{}+{T}_{2}\otimes {S}_{1} \),
  2. Tbounded linear operator1one⊗(Sbounded linear operator1one+plusSbounded linear operator2two)=equalsTbounded linear operator1one⊗Sbounded linear operator1one+plusTbounded linear operator1one⊗Sbounded linear operator2two \( {T}_{1}\otimes \mathopen{}\left({S}_{1}+{S}_{2}\right)\mathclose{}= {T}_{1}\otimes {S}_{1}+{T}_{1}\otimes {S}_{2} \),
  3. (Tbounded linear operator1one⊗Sbounded linear operator1one)⁢times(Tbounded linear operator2two⊗Sbounded linear operator2two)=equalsTbounded linear operator1one⁢timesTbounded linear operator2two⊗Sbounded linear operator1one⁢timesSbounded linear operator2two \( \mathopen{}\left({T}_{1}\otimes {S}_{1}\right)\mathclose{}\mathopen{}\left({T}_{2}\otimes {S}_{2}\right)\mathclose{}= {T}_{1}{T}_{2}\otimes {S}_{1}{S}_{2} \),
  4. ‖Tbounded linear operator1one⊗Sbounded linear operator1one‖=equals‖Tbounded linear operator1one‖⁢times‖Sbounded linear operator1one‖ \( \mathopen{}\left\lVert{}{T}_{1}\otimes {S}_{1}\right\rVert\mathclose{}= \mathopen{}\left\lVert{}{T}_{1}\right\rVert\mathclose{}\mathopen{}\left\lVert{}{S}_{1}\right\rVert\mathclose{} \),
  5. (Tbounded linear operator1one⊗Tbounded linear operator2two)*=equals(Tbounded linear operator1one)*⊗(Tbounded linear operator2two)* \( \mathopen{}\left({T}_{1}\otimes {T}_{2}\right)\mathclose{}^{*}= \mathopen{}\left({T}_{1}\right)\mathclose{}^{*}\otimes \mathopen{}\left({T}_{2}\right)\mathclose{}^{*} \).


Previous: Positive Operators back to top Next: Compact Operators